10x^2-40x-360=0

Solution for 10x^2-40x-360=0 equation:

10x^2-40x-360=0

a = 10; b = -40; c = -360;
Δ = b2-4ac
Δ = -402-4·10·(-360)
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40\sqrt{10}}{2*10}=\frac{40-40\sqrt{10}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40\sqrt{10}}{2*10}=\frac{40+40\sqrt{10}}{20}
$